AP Calculus ABmediummcq1 pt
∫ 1/(1+x²) dx =
A.arctan(x) + C
B.arcsin(x) + C
C.ln(1+x²) + C
D.-1/(1+x²) + C
Explanation
Core Concept
The integral of 1/(1+x²) is arctan(x) + C. This is a standard inverse trigonometric integral formula.
Correct Answer
Aarctan(x) + C
More Unit 6: Integration and Accumulation of Change practice questions
- hardLet $f$ be continuous with $f''(x)>0$ on $[0,2]$. If $T$ is the trapezoidal approximation of $\int_0^2 f(x)\,dx$ with equal subintervals, wh…
- hardWhich of the following equals $\int \frac{x^2+x-2}{x+1}\,dx$?
- hardWhat is the value of $\int_0^{\pi/2} \cos x\,\sin^3 x\,dx$?
- hardWhich of the following equals $\int \frac{e^{2x}+2e^x+1}{e^x}\,dx$?
- hardWhat is the value of $\int_0^2 |x-1|\,dx$?
Practice more AP Calculus AB questions with full explanations
Practice Unit 6: Integration and Accumulation of Change Questions →