AP Physics 1hardmcq1 pt

A 0.20 kg puck slides at 5.0 m/s around the inside of a frictionless vertical cone of half-angle 45°, at a constant height. The radius of its circular path is 0.50 m. The horizontal centripetal force is

A.10 N
B.2.0 N
C.20 N
D.5.0 N

Explanation

Core Concept

F = mv²/r = (0.20)(25)/0.50 = 10 N.

Correct Answer

A10 N

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