AP Physics 1mediummcq1 pt
A 1200 kg car drives over a circular hill of radius 30 m at 12 m/s (g = 10 m/s²). The normal force on the car is about
A.6200 N
B.12000 N
C.5760 N
D.17800 N
N = mg − mv²/r = 12000 − (1200)(144)/30 = 12000 − 5760 = 6240 N ≈ 6200 N.
A6200 N
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