AP Calculus ABmediummcq1 pt

What is the particular solution of dydx=4x\dfrac{dy}{dx} = 4x that satisfies y(1)=5y(1) = 5?

A.y=2x2+3y = 2x^2 + 3
B.y=2x2+5y = 2x^2 + 5
C.y=4x2+1y = 4x^2 + 1
D.y=2x21y = 2x^2 - 1

Explanation

Core Concept

Integrating gives y=2x2+Cy = 2x^2 + C; substituting (1,5)(1,5) gives 5=2+C5 = 2 + C, so C=3C = 3.

Correct Answer

Ay=2x2+3y = 2x^2 + 3

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