AP Calculus ABmediummcq1 pt

What is the particular solution of dydx=2xy\dfrac{dy}{dx} = 2xy that satisfies y(0)=3y(0) = 3?

A.y=3ex2y = 3e^{x^2}
B.y=3e2xy = 3e^{2x}
C.y=ex2+3y = e^{x^2} + 3
D.y=3x2+3y = 3x^2 + 3

Explanation

Core Concept

Separating gives lny=x2+C\ln|y| = x^2 + C, so y=Cex2y = Ce^{x^2}; the condition y(0)=3y(0)=3 forces C=3C = 3.

Correct Answer

Ay=3ex2y = 3e^{x^2}

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