AP Calculus ABmediummcq1 pt

A particle moves along a line with velocity v(t)=t24v(t)=t^2-4 meters per second. What is the net displacement of the particle over [0,4][0,4]?

A.163\frac{16}{3} meters
B.1616 meters
C.643\frac{64}{3} meters
D.00 meters

Explanation

Core Concept

The net displacement is 04(t24)dt=[t3/34t]04=64/316=16/3\int_0^4(t^2-4)\,dt=[t^3/3-4t]_0^4=64/3-16=16/3.

Correct Answer

A163\frac{16}{3} meters

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