AP Calculus ABmediummcq1 pt

A particle moves along a line so that its position is s(t)=t2s(t)=t^2 meters after tt seconds. The average velocity of the particle over the interval [2,2.5][2,\,2.5] is

A.44 m/s
B.6.256.25 m/s
C.0.50.5 m/s
D.4.54.5 m/s

Explanation

Core Concept

Compute s(2.5)s(2)2.52=6.2540.5=4.5\dfrac{s(2.5)-s(2)}{2.5-2}=\dfrac{6.25-4}{0.5}=4.5. This is the slope of the secant line on the interval.

Correct Answer

D4.54.5 m/s

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