AP Calculus ABeasymcq1 pt

If F(x)=0xt3dtF(x)=\int_0^x t^3\,dt, then F(x)=F'(x)=

A.x3x^3
B.3x23x^2
C.x44\frac{x^4}{4}
D.t3t^3

Explanation

Core Concept

By FTC part 1, F(x)F'(x) is the integrand evaluated at the upper limit: F(x)=x3F'(x)=x^3.

Correct Answer

Ax3x^3

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