AP Calculus ABhardmcq1 pt

If F(x)=xx2t2dtF(x)=\int_x^{x^2} t^2\,dt, then F(x)=F'(x)=

A.x4x2x^4-x^2
B.2x52x^5
C.2x5x22x^5-x^2
D.2x5+x22x^5+x^2

Explanation

Core Concept

Differentiating each limit, F(x)=(x2)22xx2=2x5x2F'(x)=(x^2)^2\cdot 2x-x^2=2x^5-x^2.

Correct Answer

C2x5x22x^5-x^2

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