AP Calculus ABeasymcq1 pt

Which of the following is the most general antiderivative of e3xe^{3x}?

A.13e3x+C\frac{1}{3}e^{3x}+C
B.e3x+Ce^{3x}+C
C.3e3x+C3e^{3x}+C
D.13e3x\frac{1}{3}e^{3x}

Explanation

Core Concept

Dividing by the coefficient of xx in the exponent gives 13e3x+C\frac{1}{3}e^{3x}+C.

Correct Answer

A13e3x+C\frac{1}{3}e^{3x}+C

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