AP Calculus ABmediummcq1 pt

Which of the following functions satisfies dydx=xy\dfrac{dy}{dx} = \dfrac{x}{y} and y(0)=1y(0) = 1?

A.y=x2+1y = \sqrt{x^2 + 1}
B.y=x21y = \sqrt{x^2 - 1}
C.y=x22+1y = \dfrac{x^2}{2} + 1
D.y=x2+2y = \sqrt{x^2 + 2}

Explanation

Core Concept

Differentiating gives y=xx2+1=xyy' = \dfrac{x}{\sqrt{x^2+1}} = \dfrac{x}{y}, and y(0)=1=1y(0) = \sqrt{1} = 1.

Correct Answer

Ay=x2+1y = \sqrt{x^2 + 1}

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