AP Calculus ABhardmcq1 pt
Find d/dx [sin(3x² + 2x)].
A.cos(3x² + 2x)(6x + 2)
B.cos(6x + 2)
C.-cos(3x² + 2x)(6x + 2)
D.cos(3x² + 2x)(6x)
Explanation
Core Concept
Correct. Applying the chain rule: d/dx[sin(u)] = cos(u) · du/dx, where u = 3x² + 2x and du/dx = 6x + 2.
Correct Answer
Acos(3x² + 2x)(6x + 2)
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