AP Calculus ABeasymcq1 pt
Find d/dx [cos³(2x)].
A.-6cos²(2x)sin(2x)
B.-3cos²(2x)sin(2x)
C.6cos²(2x)sin(2x)
D.-6cos(2x)sin(2x)
Correct. By the chain rule applied to [cos(2x)]³: 3cos²(2x) · (-sin(2x)) · 2 = -6cos²(2x)sin(2x).
A-6cos²(2x)sin(2x)
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