AP Calculus ABeasymcq1 ptIf f(x)=xexf(x)=\dfrac{x}{e^x}f(x)=exx, then f′(x)=f'(x)=f′(x)=A.x−1ex\dfrac{x-1}{e^x}exx−1B.1ex\dfrac{1}{e^x}ex1C.1−xex\dfrac{1-x}{e^x}ex1−xD.1−xe2x\dfrac{1-x}{e^{2x}}e2x1−x