AP Calculus ABmediummcq1 ptIf f(x)=1x2f(x)=\dfrac{1}{x^2}f(x)=x21, then f′(x)=f'(x)=f′(x)=A.−2x-\dfrac{2}{x}−x2B.2x3\dfrac{2}{x^3}x32C.−1x3-\dfrac{1}{x^3}−x31D.−2x3-\dfrac{2}{x^3}−x32