AP Calculus ABmediummcq1 pt

If x2+xy+y2=7x^2+xy+y^2=7 defines yy implicitly as a function of xx, then dydx=\dfrac{dy}{dx}=

A.2x+yx+2y-\dfrac{2x+y}{x+2y}
B.2x2y-\dfrac{2x}{2y}
C.2x+yx+2y\dfrac{2x+y}{x+2y}
D.x+yx+2y-\dfrac{x+y}{x+2y}

Explanation

Core Concept

Differentiating gives 2x+y+xdydx+2ydydx=02x+y+x\frac{dy}{dx}+2y\frac{dy}{dx}=0. Collect the dydx\frac{dy}{dx} terms and solve to get 2x+yx+2y-\frac{2x+y}{x+2y}.

Correct Answer

A2x+yx+2y-\dfrac{2x+y}{x+2y}

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