AP Calculus ABeasymcq1 pt

If x2+y2=25x^2+y^2=25 defines yy implicitly as a function of xx, then dydx=\dfrac{dy}{dx}=

A.xy\dfrac{x}{y}
B.xy-\dfrac{x}{y}
C.yx\dfrac{y}{x}
D.yx-\dfrac{y}{x}

Explanation

Core Concept

Differentiate both sides to get 2x+2ydydx=02x+2y\frac{dy}{dx}=0. Solving gives dydx=xy\frac{dy}{dx}=-\frac{x}{y}.

Correct Answer

Bxy-\dfrac{x}{y}

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