AP Calculus ABmediummcq1 pt

If f(x)=e2xcosxf(x)=e^{2x}\cos x, then f(x)=f'(x)=

A.2e2xcosx+e2xsinx2e^{2x}\cos x+e^{2x}\sin x
B.2e2xsinx-2e^{2x}\sin x
C.2e2xcosx2e^{2x}\cos x
D.2e2xcosxe2xsinx2e^{2x}\cos x-e^{2x}\sin x

Explanation

Core Concept

Use the product rule with the chain rule on the first factor. The result is 2e2xcosx+e2x(sinx)2e^{2x}\cos x+e^{2x}(-\sin x).

Correct Answer

D2e2xcosxe2xsinx2e^{2x}\cos x-e^{2x}\sin x

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