AP Physics 1hardmcq1 pt
A 1000 kg car goes over the top of a hill of radius 40 m at 20 m/s (g = 10 m/s²). The normal force on the car is
A.0 N
B.10000 N
C.20000 N
D.5000 N
mv²/r = (1000)(400)/40 = 10000 N equals mg = 10000 N, so N = 0 — the car just loses contact.
A0 N
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