AP Physics 1hardmcq1 pt
A 0.05 kg bullet at 400 m/s embeds in a 1.95 kg block (vf = 10 m/s). The kinetic energy lost is
A.3900 J
B.4000 J
C.100 J
D.2000 J
Explanation
Core Concept
Kᵢ = ½(0.05)(160000) = 4000 J; Kf = ½(2)(100) = 100 J; lost = 3900 J.
Correct Answer
A3900 J
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