AP Physics 1hardmcq1 pt
A 2.0 kg cart at 6.0 m/s collides with a 4.0 kg cart at rest on frictionless track; they stick. The impulse on the 4.0 kg cart is
A.8.0 N·s
B.12 N·s
C.4.0 N·s
D.2.0 N·s
Explanation
Core Concept
Final common v = 12/6 = 2.0 m/s; Δp of the 4.0 kg cart = (4.0)(2.0) = 8.0 N·s.
Correct Answer
A8.0 N·s
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