AP Physics 1hardmcq1 pt
A 5.0 kg bowling ball strikes a 0.16 kg pin at 6.0 m/s and knocks it forward at 9.0 m/s. The ball's speed afterward (treating the collision as head-on) is about
A.5.7 m/s
B.6.0 m/s
C.3.0 m/s
D.6.3 m/s
Explanation
Core Concept
Momentum: (5.0)(6.0) = (5.0)v + (0.16)(9.0), so v = (30 − 1.44)/5.0 ≈ 5.7 m/s.
Correct Answer
A5.7 m/s
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