AP Physics 1mediummcq1 pt
A 150 g baseball is pitched at 40 m/s and hit back at 50 m/s. The impulse delivered by the bat is
A.13.5 N·s
B.1.5 N·s
C.6.0 N·s
D.27 N·s
|Δp| = m|vf − vᵢ| = 0.15|−50 − 40| = 0.15(90) = 13.5 N·s.
A13.5 N·s
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