AP Physics 1hardmcq1 pt
A 0.50 kg ball at 4.0 m/s strikes a wall at 60° measured from the wall’s surface and rebounds symmetrically at the same speed. The magnitude of the impulse from the wall is
A.2.0 N·s
B.3.5 N·s
C.4.0 N·s
D.0 N·s
Only the perpendicular component reverses, so |Δp| = 2mv sin 60° = 2(0.50)(4.0)(0.866) ≈ 3.5 N·s.
B3.5 N·s
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