AP Physics 2mediummcq1 pt
The work function of a certain metal is 4.0 eV. What is the minimum frequency of light that can cause photoelectric emission from this metal?
A.3.0 × 10^14 Hz
B.6.0 × 10^14 Hz
C.9.7 × 10^14 Hz
D.1.2 × 10^15 Hz
Explanation
Core Concept
The minimum frequency (threshold frequency) occurs when the photon energy equals the work function: hf = φ. Using h = 4.14 × 10^-15 eV·s, we get f = φ/h = 4.0 eV / (4.14 × 10^-15 eV·s) ≈ 9.7 × 10^14 Hz.
Correct Answer
C9.7 × 10^14 Hz
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