AP Physics 2mediummcq1 pt
A 2.0 m wire carrying 5.0 A sits perpendicular to a 0.30 T field. The force is
A.3.0 N
B.0.75 N
C.1.5 N
D.6.0 N
F = ILB = (5.0)(2.0)(0.30) = 3.0 N.
A3.0 N
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