AP Chemistryhardmcq1 pt
What volume of 0.500 M HCl neutralizes 25.0 mL of 0.250 M Ba(OH)₂?
A.25.0 mL
B.12.5 mL
C.50.0 mL
D.6.25 mL
Moles OH⁻ = 2 × (0.250 × 0.0250) = 0.0125 mol. Equal moles of H⁺ needed: 0.0125 mol ÷ 0.500 M = 0.0250 L = 25.0 mL.
A25.0 mL
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