AP Chemistrymediummcq1 pt
What volume of 6.0 M HCl is needed to prepare 250 mL of 1.5 M HCl?
A.63 mL
B.25 mL
C.100 mL
D.150 mL
Explanation
Core Concept
Dilution conserves moles: M₁V₁ = M₂V₂, so V₁ = (1.5 M × 250 mL) ÷ 6.0 M = 62.5 mL ≈ 63 mL of stock acid, topped to 250 mL with water.
Correct Answer
A63 mL
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