AP Physics 1mediummcq1 pt
A uniform rod (I = (1/12)mL²) of mass 3.0 kg and length 2.0 m pivots about its center. Its moment of inertia is
A.1.0 kg·m²
B.2.0 kg·m²
C.4.0 kg·m²
D.0.50 kg·m²
Explanation
Core Concept
I = (1/12)mL² = (3.0)(4.0)/12 = 1.0 kg·m².
Correct Answer
A1.0 kg·m²
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