Three resistors of 6Ω, 3Ω, and 2Ω are connected in parallel. What is the equivalent resistance of this combination?

Core Concept

For resistors in parallel, the equivalent resistance is calculated as 1/Rₑq = 1/R1 + 1/R2 + 1/R3. Substituting the values: 1/Rₑq = 1/6 + 1/3 + 1/2 = 1/6 + 2/6 + 3/6 = 6/6 = 1. Therefore, Rₑq = 1.0 Ω.