AP Physics 1hardmcq1 pt
A spring of k = 200 N/m has a 2.0 kg mass. When the mass passes equilibrium, its speed is 3.0 m/s. The amplitude is
A.0.30 m
B.0.090 m
C.3.0 m
D.0.60 m
Explanation
Core Concept
½mv² = ½kA² at equilibrium: A = v√(m/k) = 3.0√(2/200) = 3.0(0.1) = 0.30 m.
Correct Answer
A0.30 m
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