AP Physics 1hardmcq1 pt
A spring launches a 0.10 kg ball vertically. If the spring (k = 100 N/m) was compressed 0.20 m (g = 10 m/s²), the ball's maximum height above the compressed position is
A.2.0 m
B.1.0 m
C.4.0 m
D.20 m
½kx² = mgh gives h = (½)(100)(0.04)/((0.10)(10)) = 2.0/1.0 = 2.0 m.
A2.0 m
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