AP Calculus ABmediummcq1 pt

A spherical balloon is inflated at a rate of 100π100\pi cm3^3/s. How fast is its radius increasing when the radius is 5 cm?

A.11 cm/s
B.55 cm/s
C.15\dfrac{1}{5} cm/s
D.44 cm/s

Explanation

Core Concept

Differentiating V=43πr3V=\dfrac{4}{3}\pi r^3 gives dVdt=4πr2drdt\dfrac{dV}{dt}=4\pi r^2\dfrac{dr}{dt}. Solving 100π=4π(25)drdt100\pi=4\pi(25)\dfrac{dr}{dt} gives drdt=1\dfrac{dr}{dt}=1 cm/s.

Correct Answer

A11 cm/s

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