AP Physics 1hardmcq1 pt
A solid disk (I = ½mr²) rolls without slipping down an incline of height h. Its translational speed at the bottom is
A.√(4gh/3)
B.√(2gh)
C.√(gh)
D.√(gh/2)
mgh = ½mv² + ½(½mr²)(v²/r²) = ¾mv², so v = √(4gh/3).
A√(4gh/3)
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