AP Calculus BCmediummcq1 pt
For x = t², y = t³, the second derivative d²y/dx² is
A.3/(4t)
B.3/2
C.3/(2t)
D.6t
Explanation
Core Concept
d²y/dx² = d/dx[(3/2)t] = (d/dt[(3/2)t])/(dx/dt) = (3/2)/(2t) = 3/(4t).
Correct Answer
A3/(4t)
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