AP Physics 1easymcq1 pt
A 0.50 m rod pivots at one end. A 6.0 N force acts at the far end, perpendicular to the rod. The torque about the pivot is
A.3.0 N·m
B.12 N·m
C.6.0 N·m
D.1.5 N·m
Explanation
Core Concept
τ = rF = (0.50)(6.0) = 3.0 N·m.
Correct Answer
A3.0 N·m
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