AP Physics 1hardmcq1 pt
A rod of length L and mass m pivots at one end (I = ⅓mL²). A perpendicular force F acts at the free end. The angular acceleration is
A.3F/(mL)
B.F/(mL)
C.3FL/m
D.F/(3mL)
α = τ/I = FL/(⅓mL²) = 3F/(mL).
A3F/(mL)
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