AP Calculus ABmediummcq1 pt

A rocket's height after tt seconds is h(t)=16t2+256t+40h(t)=-16t^2+256t+40 feet. What is its maximum height?

A.10641064 ft
B.10241024 ft
C.808808 ft
D.4040 ft

Explanation

Core Concept

The rocket peaks when v(t)=h(t)=32t+256=0v(t)=h'(t)=-32t+256=0, at t=8t=8. Its height is h(8)=16(64)+256(8)+40=1064h(8)=-16(64)+256(8)+40=1064 feet.

Correct Answer

A10641064 ft

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