AP Physics 2mediummcq1 pt
A 0.50 kg rock of density 2500 kg/m³ is submerged in water (ρ = 1000 kg/m³, g = 10 m/s²). The buoyant force is
A.2.0 N
B.5.0 N
C.0.50 N
D.20 N
V = m/ρ = 0.50/2500 = 2.0×10⁻⁴ m³; Fb = (1000)(2.0×10⁻⁴)(10) = 2.0 N.
A2.0 N
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