AP Physics 2easymcq1 pt

A rectangular loop of wire with dimensions 0.20 m × 0.30 m is placed in a uniform magnetic field of 0.50 T. The normal to the loop makes an angle of 30° with the magnetic field. What is the magnetic flux through the loop?

A.0.026 Wb
B.0.030 Wb
C.0.060 Wb
D.0.120 Wb

Explanation

Core Concept

Magnetic flux is given by Φ = BA cosθ, where B is the magnetic field strength, A is the area of the loop, and θ is the angle between the magnetic field and the normal to the loop. The area A = (0.20 m)(0.30 m) = 0.06 m². Therefore, Φ = (0.50 T)(0.06 m²)cos(30°) = 0.026 Wb.

Correct Answer

A0.026 Wb

More Unit 5: Magnetism and Electromagnetic Induction practice questions

Try a random question →

Practice more AP Physics 2 questions with full explanations

Practice Unit 5: Magnetism and Electromagnetic Induction Questions →