AP Chemistrymediummcq1 pt
10.0 g of N₂ reacts with excess H₂: N₂ + 3H₂ → 2NH₃. What mass of NH₃ forms? (N₂ = 28.0, NH₃ = 17.0 g/mol)
A.12.1 g
B.6.07 g
C.17.0 g
D.24.3 g
Moles N₂ = 10.0 ÷ 28.0 = 0.357 mol. The 1:2 ratio gives 0.714 mol NH₃ × 17.0 g/mol = 12.1 g.
A12.1 g
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