AP Chemistrymediummcq1 pt
For a reaction with ΔH° > 0 and ΔS° > 0, at what temperature does it become favored?
A.Above T = ΔH°/ΔS°
B.Below T = ΔH°/ΔS°
C.At all temperatures
D.Never
Explanation
Core Concept
ΔG° = 0 at T = ΔH°/ΔS°, and above that temperature the −TΔS° term dominates, making ΔG° negative.
Correct Answer
AAbove T = ΔH°/ΔS°
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