AP Chemistryeasymcq1 pt
For a reaction that is second order in a single reactant A, a plot of 1/[A] versus time is a straight line. The slope of that line equals:
A.+k, an ascending line
B.-k, a descending line
C.1/[A]0
D.the product kt
The integrated second-order law is 1/[A] = kt + 1/[A]0. Matching this to y = mx + b identifies time as x, 1/[A] as y, 1/[A]0 as the intercept, and k as the positive slope. Measuring the line's steepness therefore yields the rate constant directly. The upward tilt also signals that 1/[A], and hence the inverse concentration, grows as A is consumed.
A+k, an ascending line
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