AP Chemistryhardmcq1 pt
What is ΔG° for a reaction with K = 10 at 298 K? (R = 8.314 J/mol·K)
A.−5.7 kJ
B.+5.7 kJ
C.−13.8 kJ
D.0 kJ
Explanation
Core Concept
ΔG° = −RT ln K = −(8.314)(298)(ln 10) = −(2478)(2.303) = −5707 J ≈ −5.7 kJ. K > 1 always pairs with negative ΔG°.
Correct Answer
A−5.7 kJ
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