AP Chemistrymediummcq1 pt
A reaction has ΔH° = +40 kJ and ΔS° = +120 J/K. What is ΔG° at 500 K?
A.−20 kJ
B.+100 kJ
C.+20 kJ
D.−60 kJ
Explanation
Core Concept
ΔG° = ΔH° − TΔS° = 40 − (500 × 0.120) = 40 − 60 = −20 kJ. Favored at this temperature despite being endothermic.
Correct Answer
A−20 kJ
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