AP Calculus ABeasymcq1 pt

The position of a particle is s(t)=3t2+2t+1s(t)=3t^2+2t+1 meters at time tt seconds. What is the velocity at t=2t=2 seconds?

A.1414 m/s
B.1212 m/s
C.88 m/s
D.1616 m/s

Explanation

Core Concept

Differentiate to get v(t)=6t+2v(t)=6t+2. Substituting t=2t=2 gives 6(2)+2=146(2)+2=14 m/s.

Correct Answer

A1414 m/s

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