AP Calculus ABeasymcq1 pt

The position of a particle is s(t)=2t33t2+t+1s(t)=2t^3-3t^2+t+1 meters at time tt seconds. What is the velocity at t=3t=3 seconds?

A.3636 m/s
B.3131 m/s
C.5555 m/s
D.3737 m/s

Explanation

Core Concept

Velocity is v(t)=s(t)=6t26t+1v(t)=s'(t)=6t^2-6t+1. Substituting t=3t=3 gives 5418+1=3754-18+1=37 m/s.

Correct Answer

D3737 m/s

More Unit 4: Contextual Applications of Differentiation practice questions

Try a random question →

Practice more AP Calculus AB questions with full explanations

Practice Unit 4: Contextual Applications of Differentiation Questions →