AP Biologymediummcq1 pt
At Hardy–Weinberg equilibrium, a population has allele frequency p=0.60 for a completely dominant allele A. What fraction of individuals is expected to show the dominant phenotype?
A.0.60
B.0.36
C.0.16
D.0.84
Explanation
Core Concept
At Hardy–Weinberg equilibrium, q=1−p=0.40 and aa=q²=0.16. Both AA and Aa show the dominant phenotype, so its expected frequency is 1−0.16=0.84.
Correct Answer
D0.84
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