AP Physics 1mediummcq1 pt
A pendulum of length 0.40 m swings on Earth (g = 10 m/s², π² ≈ 10). Its period is about
A.1.3 s
B.0.20 s
C.0.63 s
D.2.5 s
T = 2π√(L/g) = 2π√(0.40/10) = 2π(0.2) ≈ 1.26 s ≈ 1.3 s.
A1.3 s
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