AP Physics 1mediummcq1 pt
A pendulum of length 1.0 m on Earth (g = 10 m/s², π² ≈ 10) has a period of about
A.2.0 s
B.1.0 s
C.6.3 s
D.4.0 s
T = 2π√(L/g) = 2π√(0.1) = 2π(0.316) ≈ 1.99 s ≈ 2.0 s.
A2.0 s
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